55=(x^2-x)/2

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Solution for 55=(x^2-x)/2 equation: 


x in (-oo:+oo)

55 = (x^2-x)/2 // - (x^2-x)/2

55-((x^2-x)/2) = 0

(-1*(x^2-x))/2+55 = 0

(-1*(x^2-x))/2+(2*55)/2 = 0

2*55-1*(x^2-x) = 0

x-x^2+110 = 0

x-x^2+110 = 0

x-x^2+110 = 0

DELTA = 1^2-(-1*4*110)

DELTA = 441

DELTA > 0

x = (441^(1/2)-1)/(-1*2) or x = (-441^(1/2)-1)/(-1*2)

x = -10 or x = 11

(x+10)*(x-11) = 0

((x+10)*(x-11))/2 = 0

((x+10)*(x-11))/2 = 0 // * 2

(x+10)*(x-11) = 0

( x+10 )

x+10 = 0 // - 10

x = -10

( x-11 )

x-11 = 0 // + 11

x = 11

x in { -10, 11 }

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